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7/(x+1)-3/(x-1)=5x/x^2-1
We move all terms to the left:
7/(x+1)-3/(x-1)-(5x/x^2-1)=0
Domain of the equation: (x+1)!=0
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
Domain of the equation: (x-1)!=0
We move all terms containing x to the left, all other terms to the right
x!=1
x∈R
Domain of the equation: x^2-1)!=0We get rid of parentheses
x∈R
7/(x+1)-3/(x-1)-5x/x^2+1=0
We calculate fractions
(7*(x-1)*x^2)/((x+1)*(x-1)*x^2)+(-3*(x+1)*x^2)/((x+1)*(x-1)*x^2)+(-5x*(x+1)*(x-1))/((x+1)*(x-1)*x^2)+1=0
We calculate terms in parentheses: +(7*(x-1)*x^2)/((x+1)*(x-1)*x^2), so:
7*(x-1)*x^2)/((x+1)*(x-1)*x^2
We multiply all the terms by the denominator
7*(x-1)*x^2)
We multiply parentheses
-7x^3+7x
We do not support expression: x^3
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